sofiyaleb3
sofiyaleb3
12-05-2018
Mathematics
contestada
Geometry Problem (PIC)
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gmany
gmany
13-05-2018
Look at the picture.
[tex]\Delta ADC\ and\ \Delta CDB\ are\ similar\ therefore\\\\\dfrac{y}{4}=\dfrac{9}{y}\ \ \ \ |cross\ multiply\\\\y\cdot y=4\cdot9\\\\y^2=36\to y=\sqrt{36}\to y=6[/tex]
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