Problem 4 You have to assume something or it is unsolvable. We will assume that the triangle is divided into 2 smaller right triangles. They will be subject to a^2 + b^2 = c^2 a = 32/2 = 16 b = h c = 20 20^2 = 16^2 + h^2 400 = 256 + h^2 Subtract 256 400 - 256 = h^2 144 = h^2 h = sqrt(144) h = 12
Now we can find the area. h = 12 base = b = 32
Area = 1/2 * b * h Area = 1/2 * 32 * 12 Area = 192 square inches.
Problem 5 Same assumption. Same method. a^2 + b^2 = c^2 c = 25 b = 7 h = ??? h^2 + 7^2 = 25^2 h^2 + 49 = 625 h^2 = 625 - 49 h^2 = 576 h = sqrt(576) h = 24
