Answer:
[tex]x=\frac{-3\pm\sqrt{17}}{2}[/tex]
Step-by-step explanation:
We have been given an equation [tex]x^2+3x-2=0[/tex]. We are asked to solve the given equation.
To solve our given equation, we will use quadratic formula.
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
Substitute the values:
[tex]x=\frac{-3\pm\sqrt{3^2-4(1)(-2)}}{2(1)}[/tex]
[tex]x=\frac{-3\pm\sqrt{9+8}}{2}[/tex]
[tex]x=\frac{-3\pm\sqrt{17}}{2}[/tex]
Therefore, option D is the correct choice.
