eclipsemods6801 eclipsemods6801
  • 14-12-2017
  • Mathematics
contestada

Prove by contradiction that there do not exist integers m and n such that 14m+21n=100

Respuesta :

jimthompson5910 jimthompson5910
  • 14-12-2017
You can factor the left hand side to get
14m+21n = 100
7*(2m+3n) = 100
7*x = 100
where x = 2m+3n is an integer

There are no solutions to 7x = 100 since 7 is not a factor of 100 (ie 7|100 is false). So that means there are no solutions to the original diophantine equation.
Answer Link

Otras preguntas

The expected o-c-h angle in this molecule is degrees. the expected hybridization at the central carbon is
the product of a number X and 6 is 4 more than the product of the number and 3/8 which answer represents the situation
Ravi pays a $7 monthly fee plus .7cents per minute. Last month, ravis long distance bill was 15.96. For how many minutes was ravi billed?
Why does do campo’s expedition matter to Oklahoma
Main idea? 1)A firm handshake at the beginning of an interview is important 2)Do not ask about salary during a job interview if you can help it 3)follow these q
which cultures influenced the art of Joaquin Torres Garcia
Atticus says, “You never really understand a person until you consider things from his point of view--until you climb into his skin and walk around in it” (Lee
What helped stimulate the development of renaissance culture
Simplify be combining like terms: -3+6x-18-22x
7. Which human activity will most likely contribute to ozone layer destruction? cutting down trees to build a library using fertilizer to grow bean crops planti