Arahelp
Arahelp
15-09-2017
Mathematics
contestada
CAN SOMEONE PLEASE HELP ME!
Respuesta :
mreijepatmat
mreijepatmat
15-09-2017
1st Problem:
2r≤ 3r - 8
2r - 3r ≤ - 8
- r ≤ - 8 and r≥8, then the solution is {8,9,10}
2nd Problem
16 - r ≤ 8
-r ≤ 8 -16
-r ≤ - 8 and r≥8, then the solution is {8,9,10}
Answer Link
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