samcanton samcanton
  • 15-08-2017
  • Mathematics
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Help identify BD in terms of TT

Help identify BD in terms of TT class=

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Banabanana
Banabanana Banabanana
  • 15-08-2017
[tex]arc \ length \ of \ BD = \pi r ( \frac{\angle BPD}{180} ) \\ \\ \angle BPD=\angle APC=92^o \ \ \text{[vertical angle]} \\ \\ arcBD= \pi *8 *\frac{92}{180} \approx 4.09 \pi \ in \approx12.85 in [/tex]

Answer: ≈4.09π in. ≈12.85 in.
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