nothanksok nothanksok
  • 15-07-2017
  • Mathematics
contestada

Solve for c of the right triangle

Solve for c of the right triangle class=

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owensmith6
owensmith6 owensmith6
  • 15-07-2017
In order to solve this triangle we must use cosine law:
[tex]c^{2} = a^{2} + b^{2} - 2ab*cosC[/tex]

Now let's plug in the values we are given:
[tex]c^{2} = 5^{2} + 8^{2} - 2(5)(8) * cos 67[/tex]
[tex]c^{2} = 25 + 64 - 80*cos67[/tex]
[tex]c = \sqrt{80-cos67}[/tex]

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wolf1728
wolf1728 wolf1728
  • 15-07-2017
From the Law of Cosines, we know
b=8 a=5 angle C=67
side c² = a² + b² -2ab • cos(C)
side c² = 5^2 +8^2 -2*5*8 * cos (67)
side c² = 25 + 64 -(80*.39073)
side c² = 89 - 31.2584
side c² = 57.7416
side c = 7.5987893773



Answer Link

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