Find the hypotenuse of the larger triangle. Use the pythagorean theorem a^2 + b^2 = c^2 5^2 + 12^2 = c^2 169 = c^2 c^2 = 169 c = sqrt(169) c = 13
The two segments of 12x and 14x add up to this 13 unit long hypotenuse
So, 12x+14x = 13 26x = 13 26x/26 = 13/26 x = 1/2
Answer is choice E) 1/2
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Problem 48)
This one is a bit tricky. P1 and P2 are known P1 = -2 P2 = -1 P3,P4,P5 are unknown. But it looks like maybe P3 = 0.25, P4 = 0.75, P5 = 1.5 or roughly close to it
So, P1*P2*P3*P4*P5 = (-2)*(-1)*0.25*0.75*1.5 = 0.5625 which is closest to 2/3 = 0.67
