ka of 0.0400 M solution of HClO2, pH = 1.80

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14-04-2017
Chemistry

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ka of 0.0400 M solution of HClO2, pH = 1.80

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Hagrid Hagrid · Answer 1 · 2017-04-27T18:01:25+02:00

The Ka is 0.0104.

To solve for the Ka, the formula is Ka = [H+][ClO-]/[HClO]. In order to determine the value of H+, the formula is H+ = 10^-pH (the pH here is 1.80). This yields 0.015848931924611134. In the ICE table, since H+ is the same value as ClO, then the ClO is also 0.015848931924611134. The HClO is the 0.04 - 0.015848931924611134. Substituting the values to the earlier mentioned equation, the answer is 0.01040072606175673227903507631149 or simply, 0.0104.