lnkhprovip10268 lnkhprovip10268
  • 11-10-2022
  • Mathematics
contestada

If a and b are integers such that -6 ≤ a ≤ 3 and -4 ≤ b < 5, what is the least possible value of a times b?

Respuesta :

yazireth16859 yazireth16859
  • 11-10-2022

SOLUTION

From the question, it means that

[tex]\begin{gathered} a=-6,-5,-4\text{ . . . . . .3} \\ b=-4,-3,-2\text{ .. .. . . . . .4} \end{gathered}[/tex]

The least possible value of a and will be a ngative number, gotten by multiplying a negative value by a positive value. So this should be

the smallest value of a, that is the -6 multiplied by the biggest value of b = 4

[tex]-6\times4=-24[/tex]

Hence the answer is -24

Answer Link

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