arcustomshanny arcustomshanny

11-09-2022
Chemistry

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Calculate the joules lost when 21 g of water cools from 86 ∘C to 67 ∘C

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maidotmengesha maidotmengesha

11-09-2022

Answer: -1.67 KJ

Explanation:

Given- m of water= 21g

Final temperature- 67°C

Initial temperature- 86°C

Specific heat capacity of water ( c)= 4.182 J/g°C

Solution

Q= mcΔT

Q= 21g* 4.182J/g°C*(67°C-86°C) = -1669J

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