nc2ghgxrvp nc2ghgxrvp
  • 14-07-2022
  • Mathematics
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The problem: take two solutions and plug them into the original equation. To check for extraneous solutions.

The problem take two solutions and plug them into the original equation To check for extraneous solutions class=

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sangers1959 sangers1959
  • 14-07-2022

Answer: х=3.

Step-by-step explanation:

А point is missing here: determining the allowable values of x for this equation.

1. Consider the right side of the equation:

The root expression 2x+3 must be greater than or equal to 0.

2x+3≥0

2x≥-3\ |:2

x≥-1,5.

2. Consider the left side of the equation:

the left side of the equation must be greater than or equal to 0.

x≥0.

We get x≥0.         ⇒

х=3 ∈ х≥0

х=-1 ∉ х≥0.

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