jake4157 jake4157
  • 13-06-2022
  • Mathematics
contestada

Solve cos^2 (B) + 3cos(B) + 2 = 0 for
B, 0 < B < 360

Please help

Respuesta :

culveryolanda46
culveryolanda46 culveryolanda46
  • 13-06-2022

Step-by-step explanation:

[tex] \cos {}^{2} (b) + 3 \cos(b) + 2 = 0[/tex]

[tex]( \cos(b) + 2)( \cos(b) + 1) = 0[/tex]

[tex] \cos(b) = - 2[/tex]

Cosine have a range of [-1,1] so b is undefined for the first factor

[tex] \cos(b) = - 1[/tex]

[tex]b = 180[/tex]

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