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in need of some help with this question please~

when 4g of oxygen gas reacts with excess of hydrogen gas, the volume of water vapour produced at (STP) is ....... L ( H = 1 , O = 16).

a) 22.4
b) 44.8
c) 11.2
d) 5.6

an explanation would be great for future reference <3 thank you in advance!
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in need of some help with this question pleasewhen 4g of oxygen gas reacts with excess of hydrogen gas the volume of water vapour produced at STP is L H 1 O 16a class=

Respuesta :

Answer:

5.60 Liters at STP

Explanation:

First you need the balanced reaction equation

2 H2 +  O2   ====>   2  H2O

4 g of oxygen ( O2 )  is   4/(15.999*2) moles of O2     (using periodic table)

  Twice the number of moles of H2O re produced   (from equation)

     at STP the volume of a mole of gas is 22.4 liter/ mole

       put all of this together  

         2 *   4 / (15.999*2) moles * 22.4 L/mole = 5.60 L

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