Answer:
64 m³
Step-by-step explanation:
Formula
[tex]\textsf{Volume of a square based pyramid}=\dfrac{1}{3}a^2h[/tex]
where:
- a = side length
- h = perpendicular height
Given:
Substituting the given values into the formula:
[tex]\begin{aligned}\implies \textsf{Volume}& =\dfrac{1}{3} \cdot 8^2 \cdot 3\\\\& = \dfrac{3}{3} \cdot 64\\\\& = 1 \cdot 64\\\\& = 64\:\sf m^3\end{aligned}[/tex]
