Answer:
A' = (- 3, 0)
Step-by-step explanation:
[tex]A' = (x + 3, \: y - 2) \\ \\ \implies \: A' = ( - 6+ 3, \: 2 - 2) \\ \\ \implies \: A' = ( - 3, \: 0) [/tex]
A' = (-3, 0)
Pre-Image coordinate:
A (-6, 2)
Translation: (x, y) --> (x + 3, y - 2)
(-6 + 3, 2 - 2)
(-3 0)
Image coordinate:
hope this helps!! p.s. i really need brainliest :)
