prashna23
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  • 14-02-2022
  • Mathematics
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(If cosA/2=1/2. find the value of sinA.)​

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Аноним Аноним
  • 14-02-2022

[tex]\\ \rm\hookrightarrow cosA/2=1/2[/tex]

[tex]\\ \rm\hookrightarrow 2cosA=2[/tex]

[tex]\\ \rm\hookrightarrow cosA=1[/tex]

Now

[tex]\\ \rm\hookrightarrow sinA=\sqrt{1-cos^2A}[/tex]

[tex]\\ \rm\hookrightarrow sinA=\sqrt{1-1^2}[/tex]

[tex]\\ \rm\hookrightarrow sinA=0[/tex]

Here

  • A=0°
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