Respuesta :

fieryanswererft

Given radius: [tex]3x^9 y^{11}[/tex]

Formula for area: πr²

Area of circle:

( [tex]\pi 3x^9 y^{11}[/tex] )²

[tex]\pi 3^2x^{9*2 }y^{11*2}[/tex]

[tex]9\pi x^{18}y^{22}[/tex]

Answer: [tex]9\pi x^{18}y^{22}[/tex]

Xignerso

Formula for area: [tex]\pi {r}^{2} [/tex]

Area of circle:

[tex](\pi3 {x}^{9} {y}^{11} {)}^{2} [/tex]

[tex]\pi {3}^{2} {x}^{9}{ \times }^{2} {y}^{11} { \times }^{2} [/tex]

[tex]9\pi {x}^{18} {y}^{22} [/tex]

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