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15-11-2021
Mathematics

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A man's age is three times his son's age. Ten years ago, he was five times his son's
age. By forming two equations and solving them simultaneously, find both of their ages.

Respuesta :

bijinvarghese26 bijinvarghese26

15-11-2021

Answer:

Step-by-step explanation:

son age be x

Aman age is 3x

ten years ago

son age x-10

aman age 3x -10

A.T.Q

5(x-10) = 3x -10

5x -50 = 3x - 10

2x = 40

x =20

3x=60

son present age =20

aman present age = 60

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