Answer:
[tex]\left(6x^2-4x-5\right)\left(2x^2+3x\right)[/tex]
[tex]=6x^2\cdot \:2x^2+6x^2\cdot \:3x+\left(-4x\right)\cdot \:2x^2+\left(-4x\right)\cdot \:3x+\left(-5\right)\cdot \:2x^2+\left(-5\right)\cdot \:3x[/tex]
[tex]=6\cdot \:2x^2x^2+6\cdot \:3x^2x-4\cdot \:2x^2x-4\cdot \:3xx-5\cdot \:2x^2-5\cdot \:3x[/tex]
[tex]=12x^4+10x^3-22x^2-15x[/tex]
OAmalOHopeO
