amvo24 amvo24
  • 12-07-2021
  • Mathematics
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Аноним Аноним
  • 12-07-2021

Answer:

[tex]{ \tt{ \sin( \theta) = \frac{opposite}{hypotenuse} }} \\ { \tt{ \sin(55 \degree) = \frac{x}{15} }} \\ x = 15 \sin(55 \degree) \\{ \boxed{ \bf{ x = 12.29 \: }}} \: feet[/tex]

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