happyjellycup happyjellycup
  • 14-06-2021
  • Mathematics
contestada

1) The population of Leafy Lake starts at 3,000 and grows by 25% every year. What will the population be in 6 years?

how do I solve it

Respuesta :

Imbadatmath06
Imbadatmath06 Imbadatmath06
  • 14-06-2021
X/3,000 = 25/100
100x = 3,000x25
100x = 75,000
100x/100 = 75,000/100
X = 750

750x6 = 4,500
Every year the population goes up by 750, in 6 years the population would be 4,500 people.
Answer Link
devishri1977
devishri1977 devishri1977
  • 14-06-2021

Answer:

Step-by-step explanation:

Rate of increase = r = 25%

n = number of years = 6

P = Current population = 3000

Population after n years = [tex]P*(1 + \frac{r}{100})^{n}[/tex]

            [tex]= 3000 * (1 +0.25)^{6}\\\\= 3000 * (1.25)^{6}\\\\= 3000 * 3.8\\\\= 11400=[/tex]

Answer Link

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