Honeyjjk Honeyjjk

13-05-2021
Mathematics

contestada

3sin²60°+3/4cot²30°-2cosec²60°-3/4tan²30°=19/12{Full process , please^^}

Respuesta :

13-05-2021

Answer:

3( root 3 /2)^2 + 3/4 (root 3 )^2 - 2(2/ root 3) ^2 - 3/4 (1/root3)^2

= 3 ×3 /4 + 3 × 3 /4 - 2 ×4 /3 - 3/4 × 1/3

= 9/4 + 9/4 -8/ 3 - 1/4

= 9/4 + 9/4 - 1/4 - 8/3

= 17/4 - 8/3

=( 17 × 3 - 8 × 4 )/12

= (54 -32)/12

= 19 /12

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