Answer:
i got u my guy ez pz
Step-by-step explanation: o yeh i forgot the answer
[tex] \frac{1}{y + 8} [/tex]
Step-by-step explanation:
[tex] \frac{ {2y}^{3} }{ {2y}^{4} + {16y}^{3} } = \frac{ {2y}^{3} }{ {2y}^{3} ( y + 8)} = \frac{1}{y + 8} [/tex]
