genesisssportillo genesisssportillo
  • 15-03-2021
  • Mathematics
contestada

Given cos(O)=3/5 and tan(O)

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abidemiokin
abidemiokin abidemiokin
  • 20-03-2021

Answer:

Tan(O) = 4/3

Step-by-step explanation:

According to SOH CAH TOA

cos theta = adj/hyp

cosO = 3/4

adj = 3

hyp = 5

Get the opposite

Using pythagoras theorem

opp^2 = hyp^2-adj^2

opp^2 = 5^2 - 3^2

opp^2 = 25-9

opp^2 = 16

opp = 4

Tan (O) = opp/adj

Tan(O) = 4/3

Hence Tan(O) = 4/3

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