lolburger
lolburger lolburger
  • 13-03-2021
  • Mathematics
contestada

need help pls geometry question

need help pls geometry question class=

Respuesta :

akposevictor
akposevictor akposevictor
  • 18-03-2021

Answer:

55.94°

Step-by-step explanation:

Reference angle = x

Hyp = 25

Adjacent = 14

Apply CAH:

[tex] Cos(x) = \frac{Adj}{Hyp} [/tex]

[tex] Cos(x) = \frac{14}{25} [/tex]

[tex] x = Cos^{-1}(\frac{14}{25}) [/tex]

x = 55.9442023° ≈ 55.94° (to 2 d.p)

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