Answer:
0.25 mole of H₂
Explanation:
The equation for the reaction is given below:
Mg + 2HCl —> MgCl₂ + H₂
From the question given above, we were told that the reaction produced 5.6 L of H₂.
Thus, we can obtain obtain the number of mole of H₂ that occupied 5.6 L at STP as follow:
1 mole of H₂ occupied 22.4 L at STP.
Therefore, Xmol of H₂ will occupy 5.6 L at STP i.e
Xmol of H₂ = 5.6 / 22.4
Xmol of H₂ = 0.25 mole
Therefore, 0.25 mole of H₂ were obtained from the reaction.
