kballday
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Use the discriminant to determine the number of real solutions to the quadratic equation.
6a2−11a+9=0
What is the number of real solutions?
Select the correct answer below:
0

1

2

Respuesta :

Answer:

0

Step-by-step explanation:

Use discramnt formula

[tex]b {}^{2} - 4ac[/tex]

Where 6 is a, 11 is b and 9 is c

[tex]11 {}^{2} - 4(6)(9) [/tex]

[tex]121 - 216 = - 95[/tex]

Since the discramnt is negative, there are no real solutions and it will only produce imaginary solutions

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