Answer:
(a) f(x) = 4x+1 (b) x = -1/4
Explanation:
Given that,
[tex]f(x) = 2x^2 + x - 6[/tex]
(a) We need to find f'(x).
[tex]f'(x)=\dfrac{d}{dx}(2x^2+x-6)\\\\=4x+1[/tex]
(b) We need to find the value of x when f'(x) =0
Put f'(x) = 0
4x+1 = 0
[tex]4x=-1\\\\x=\dfrac{-1}{4}[/tex]
So, the value is -1/4 when f'(x) = 0.
