Answer:
37.9g of carbon 14 remains
Explanation:
The radioactive decay of an atom follows the equation:
Ln[A] = -kt + Ln[A]₀
Where [A] is amount of isotope after time t, k is decay constant and [A]₀ initial amount of the isotope.
We can find k from half-life using:
k = ln 2 / Half-Life
k = ln 2 / 5730 years
k = 1.2097x10⁻⁴ yrs⁻¹
Replacing in the equation all values:
Ln[A] = -1.2097x10⁻⁴ yrs⁻¹*2292yrs + Ln[50g]
Ln[A] = 3.635
[A] = 37.9g of carbon 14 remains
