Mass of NaOH required = 12 g
Further explanation
Given
500 ml solution = 0.5 L
Molarity = 0.6 mol / L
Required
mass of NaOH
Solution
Molarity = moles of solute per liter of solution
M = n / V
solute = NaOH
moles of solute = n = M x V
n = 0.6 x 0.5
n = 0.3 moles
Mass of NaOH = mol x MW
mass = 0.3 x 40 = 12 g
