Answer:
a + b)2 = a2 + 2ab + b2
(a + b)3 = a3 + 3a2b + 3ab2 + b3
(a + b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4
a2 - b2 = (a - b)(a + b)
a2 + b2 = (a - bi)(a + bi)
a3 - b3 = (a - b)(a2 + ab + b2)
a3 + b3 = (a + b)(a2 - ab + b2)
a4 + b4 = (a2 + √2ab + b2)(a2 - √2ab + b2)
an - bn = (a - b)(an-1 + an-2b + ... + bn-1), for n even
an + bn = (a + b)(an-1 - an-2b - ... - bn-1), for n odd
Step-by-step explanation:
