joe55w262661 joe55w262661
  • 14-12-2020
  • Mathematics
contestada

AD = DB and AE = EC
m AED = 32
EF = 6
m ECF = ?

AD DB and AE EC m AED 32 EF 6 m ECF class=

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tamaralezh tamaralezh
  • 14-12-2020
First of all pay attention to triangle DEF. m DEF=90 m AED=32 so m FEC= 180-(90+32)=58. Then if m FEC is 58 the m ECF=90-58=32
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