myanpatel1 myanpatel1

13-12-2020
Mathematics

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I have attached question. I really need help on part B.

I have attached question I really need help on part B class=

Respuesta :

Аноним Аноним

13-12-2020

Answer:

[see below]

Step-by-step explanation:

[tex]y=x^2+1; y=4\\\\4=x^2+1\\\\4-1=x^2+1-1\\\\3=x^2\\\\\sqrt{3}=\sqrt{x^2}\\\\ \boxed{1.7; -1.7=x}[/tex]

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