bethanypaul bethanypaul

12-12-2020
Mathematics

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umairkazi924 umairkazi924

12-12-2020

[tex] {a}^{b} \times {a}^{c} = {a}^{(b + c)} [/tex]

[tex] \frac{ {a}^{b} }{ {a}^{c} } = {a}^{(b - c)} [/tex]

[tex] {a}^{c} \times {b}^{c} = {ab}^{c} [/tex]

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