thatfemalediaz943 thatfemalediaz943

12-12-2020
Computers and Technology

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You have a Direct Mapped cache with following parameters
Cache Data Size (C) 128
Block Size (b) 4
After partitioning the address, which is 32 bits big, into Tag, Set, and Offset, how many bits will be in each field?

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owen6929 owen6929

12-12-2020

Yes... so it would be 134 seeing as, 128 and 4 both common denominators.. and the offset would be to the 40%

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