C5henielly5issy
C5henielly5issy C5henielly5issy
  • 13-10-2016
  • Mathematics
contestada

Solve sin 4x - cos 2x = 0.

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HomertheGenius
HomertheGenius HomertheGenius
  • 22-10-2016
sin 4 x - cos 2 x = 0
2 sin 2 x cos 2 x - cos 2 x = 0
cos 2 x ( 2 sin 2 x - 1 ) = 0
cos 2 x = 0
2 x = π/2 + nπ   /  : 2
x 1 =  π/4 + nπ/2,  n ∈ Z
2 sin 2 x - 1 = 0
2 sin 2 x = 1
sin 2 x = 1/2
2 x = π/6 + 2 nπ
2 x = 5π/6 + 2 nπ
x 2 = π/12 + nπ
x 3 = 5π/12 + nπ , n ∈ Z
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