princesschone princesschone

13-11-2014
Mathematics

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how do you solve this equation by factoring?
2X(squared)-5X-3=0

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13-11-2014

[tex]2x^2-5x-3=0\ \ \ \ | write\ -5x\ as\ -6x+x\\\\ 2x^2-6x+x-3=0\\\\ x(2x+1)-3(2x+1)=0\\\\ (x-3)(2x+1)=0\\\\ x=3\ \ or\ \ 2x=-1\\\\ x=3\ \ \ or\ \ \ x=-\frac{1}{2}[/tex]

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Аноним Аноним

13-11-2014

the factors of 2 are one and two... the factors of -3 are negative 3 and 1. (2X-1)(X-3)

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