12-10-2020
Mathematics

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please solve it
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CSMedrano CSMedrano

12-10-2020

Answer:

1

Step-by-step explanation:

[tex](3^{n-1})\cdot(3^{1-n})\\\\=3^{n-1+1-n}\\\\\longrightarrow n-1+1-n=(n-n)+(-1+1)=0+0=0\\\\=3^{0}\\\\=1[/tex]

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