Answer:
±2/11
Step-by-step explanation:
Take the square root of both sides of the equation:
[tex]\sqrt{x^2}=\sqrt{\dfrac{4}{121}}\\\\\boxed{x=\pm\dfrac{2}{11}}[/tex]
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Here, we need to recognize that (-2/11)^2 = (2/11)^2 = 4/121, so both the positive and negative roots of 4/121 are solutions to the equation.
