Respuesta :

dalendrk
[tex]\log_ab=c\iff a^c=b\\\log_ab^c=c\log_ab\\\log_aa=1\\a^{-1}=\dfrac{1}{a}\\\\\log_2\dfrac{1}{64}=\log_264^{-1}=-\log_264=-\log_22^6=-6\log_22=-6[/tex]
meerkat18
The correct answer among the choices provided is the first option. When log (base 2) 1/64 is evaluated, the answer is -6. The first step is to change the logarithmic function into an exponential form. 2^(-6) = 1/64 is the correct exponential function.

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