Answer:
Hey there!
5(v+3)-10v>-10
5v+15-10v>-10
-5v+15>-10
-5v>-25
v<5
Let me know if this helps :)
[tex]\Huge \boxed{v < 5}[/tex]
Step-by-step explanation:
5(v + 3) - 10v > -10
Expand brackets.
5v + 15 - 10v > -10
Combine like terms.
-5v + 15 > -10
Subtract 15 from both parts.
-5v > -25
Divide both parts by -5 (flip sign).
v < 5
