Answer:
s is [tex]s =15.3[/tex]
Step-by-step explanation:
From the question we are told that
The data is
Generally the mean is evaluated as
[tex]\= x = \frac{84+ 85+ 83+ 63+ 61+100+ 98}{7}[/tex]
[tex]\= x = 82[/tex]
The standard deviation is mathematically represented as
[tex]s = \frac{\sum (x- \= x)^2}{n-1}[/tex]
[tex]s =\sqrt{ \frac{ (84-82)^2+ (85-82)^2 +( 83-82 )^2 +(63-82) ^2 + ( 61-82)^2,+ (100-82)^2 + (98-82)^2}{7-1}}[/tex]
[tex]s =15.3[/tex]
