Answer:
70,5.
Step-by-step explanation:
Let's find QS.
∠QHS = 90º, so:
[tex]QS^2 = a^2+(\frac{b}{2})^2\\ QS^2 = (2\sqrt{11})^2+(\frac{34}{2})^2\\ QS^2 = 4*11 + 17^2\\ QS^2 = 44+289 = 333 \\ QS = \sqrt{333} = \sqrt{3*3*37} = 3\sqrt{37}[/tex]
QS = QR = [tex]3\sqrt{37}[/tex]
[tex]P = QR+QS+RS\\ P = 3\sqrt{37} + 3\sqrt{37} + 34\\ P = 6\sqrt{37} + 34[/tex]
[tex]\sqrt{37} = 6,08276...[/tex]
[tex]P = 6*6,08276+34 = 36,48+34 = 70,4965...[/tex] [tex]= 70,5[/tex]
