The resulting value of [tex]tan\frac{11 \pi}{6}[/tex] is [tex]-\frac{\sqrt{3} }{3}[/tex]
Trigonometry identity
[tex]tan\frac{11 \pi}{6}[/tex]
Express the radians in degrees to have:
[tex]tan330=tan(360-30)[/tex]
Since
[tex]tan(360-\theta)=-tan \theta\\tan(360-30)=-tan 30 = -\frac{\sqrt{3}}{3}[/tex]
Hence the resulting value of [tex]tan\frac{11 \pi}{6}[/tex] is [tex]-\frac{\sqrt{3} }{3}[/tex]
Learn more on trigonometry here: https://brainly.com/question/24349828
