urbeardisweird urbeardisweird
  • 12-05-2020
  • Mathematics
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2x+3y=13
4x-y=2
solve the simaltaneous equation

2x3y13 4xy2 solve the simaltaneous equation class=

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nonsibi
nonsibi nonsibi
  • 12-05-2020

Solve by substitution. We begin by manipulating the second equation (solving for y).

2x+3y=13

4x-y=-2 => -y=-4x-2 => y=4x+2

Now substitute "4x+2" for y into the first equation because y=4x+2.

2x+3y=13 becomes 2x+3(4x+2)=13

Now solve for x.

2x+3(4x+2)=13

2x+12x+6=13

14x=7

x=1/2

Now we can solve for y because we know what x is.

y=4x+2 => y=4(1/2)+2 = y=4

answer: x=1/2, y=4, intersection point (1/2,4)

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