Answer: 0.33 moles
Explanation:
Given that,
Amount of moles of Na2CO3 (n) = ?
Mass of Na2CO3 in grams = 35g
For molar mass of Na2CO3, use the molar masses as follows:
Sodium, Na = 23g;
Carbon, C= 12g
Oxygen, O = 16g
Na2CO3 = (23g x 2) + 12g + (16g x 3g)
= 46g + 12g + 48g
= 106g/mol
Since, n = mass in grams / molar mass
n = 35g / 106g/mol
n = 0.33mole
Thus, 0.33 moles of Na2Co3 is needed to produce 35g of Na2Co3
