Damian6589 Damian6589
  • 14-07-2016
  • Mathematics
contestada

what does 7^x=21 in a logarithmic equation

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Аноним Аноним
  • 14-07-2016
loga x=n ⇔ a^n=x
log₇ 21=x

x=log ₇ 21
x=ln 21 / ln7=1.564575034...

Answer: x=log₇ 21
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