Answer:
|DB| = 6
Step-by-step explanation:
If ABCD is a rhombus then the diagonals AC and BD are perpendicular and intersect in half.
Let E be the point of intersection of the diagonals.
Therefore:
AE ≅ EC and DE ≅ EB ⇒ |AE| = |EC| and |DE| = |EB|.
DB = DE + EB
|EB| = 3 ⇒ |DB| = 3 + 3 = 6
ABCD it's not a rectangle because in each rectangle diagonals are congruent and intersect in half.
