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14-02-2020
Physics

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What is the de Broglie wavelength (in nanometers) associated with a 2.70−g Ping-Pong ball traveling at 15.3 mph? Enter your answer in scientific notation.

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mshahzaib247 mshahzaib247

15-02-2020

Answer:

λ = 3.588 x 10^-44 nm

Explanation:

λ = h / m v

Where λ is the de Brogile wavelength

m = 2.70g, v = 15.3 mph = 6.839712 ms^-1

λ = 6.626 x 10^-34 / 2.70 x 6.839712 = 3.588 x 10^-44 nm

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